1. On dividing the polynomial 9x. power 4 - 4x sq + 5 by another polynomial 3r2 + x - 1 the remainder comes out to be ax-b.
Find a and b.
2. If the ratio of the roots of equation px sq + qx +q
0
is a:b, prove that
root a by b plus root b by a plus root q by p is equal to 0
these are 2 ques please solve these ques completely and please don't give wrong ans....
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Answer:
Answer: a= 3 & b= -7
Step-by-step explanation:
Step-by-step explanation:given r(x)
= ax-b. Let us find out the remainder
that is obtained by dividing 9x^4-4x^2+5 by 3x^2+x+1.
3x^2+x+1 | 9x^4 -4x^2 +5 | 3x^2 -x -2
9x^4 +3x^2 +3x^3
- - -
_________________________
-3x^3 -7x^2 +5
-3x^3 - x^2 -x
+ + +
_______________________
-6x^2 +x +5
-6x^2 -2x -2
+ + +
_________________________
3x +7
Given remainder =ax-b. And remainder we have found now is 3x+7.
On comparing these two, we get: a=3 & b= -7
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