Question

1. On dividing the polynomial 9x. power 4 - 4x sq + 5 by another polynomial 3r2 + x - 1 the remainder comes out to be ax-b.
Find a and b.
2. If the ratio of the roots of equation px sq + qx +q
0
is a:b, prove that

root a by b plus root b by a plus root q by p is equal to 0



these are 2 ques please solve these ques completely and please don't give wrong ans....​

Answer 1

Answer:

Answer: a= 3 & b= -7

Step-by-step explanation:

Step-by-step explanation:given r(x)

= ax-b. Let us find out the remainder

that is obtained by dividing 9x^4-4x^2+5 by 3x^2+x+1.

3x^2+x+1 | 9x^4 -4x^2 +5 | 3x^2 -x -2

9x^4 +3x^2 +3x^3

- - -

_________________________

-3x^3 -7x^2 +5

-3x^3 - x^2 -x

+ + +

_______________________

-6x^2 +x +5

-6x^2 -2x -2

+ + +

_________________________

3x +7

Given remainder =ax-b. And remainder we have found now is 3x+7.

On comparing these two, we get: a=3 & b= -7