Question

1. P.
In right angled APQR,
ZR=40°, then
cos 50º = ...
41
40°
40
R
O 40/41
O 9/41
O 41/40
O 9/40​

Answer 1

Answer:

R.E.F.image

In △PQR,∠PQR=90

∘

BY Pythagoras theorem,

PR

2

=PQ

2

+QR

2

⇒(5)

2

=PQ

2

+(4)

2

⇒(5)

2

−(4)

2

=PQ

2

⇒PQ

2

=25−16

⇒PQ

2

=9

⇒PQ=

9

⇒PQ=3

tanR=

QR

PQ

=

4

3

.