1. Prove that a conical tent of given capacity will require the least amount of canvas when the height is root 2times the radius of the base.
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Capacity is equal, that means volume is constant.
To Prove that- The Surface Area will be minimum if the height is √2 times the radius
Proof- v=volume
v1=v2
v1=1/3r²h
so, SA1= rl
L1=√h²+r²
SA1=r√h²+r²
Now v2 in which h is √2 times tthe radius
v2=1/3r²√2r (h=√2r)
SA2=rl
L2= √r²+(√2r)²
L2=√3r²=r√3
SA2= r*r√3
SA2=r²√3
Now we wil compare the volume
v1=v2
1/3r²h =1/3r²√2r
Hence we will get the answer!
To Prove that- The Surface Area will be minimum if the height is √2 times the radius
Proof- v=volume
v1=v2
v1=1/3r²h
so, SA1= rl
L1=√h²+r²
SA1=r√h²+r²
Now v2 in which h is √2 times tthe radius
v2=1/3r²√2r (h=√2r)
SA2=rl
L2= √r²+(√2r)²
L2=√3r²=r√3
SA2= r*r√3
SA2=r²√3
Now we wil compare the volume
v1=v2
1/3r²h =1/3r²√2r
Hence we will get the answer!
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