Question

1.Prove that `(A u B)-C=(A-C)u(B-C)`




Please answer this question
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

(A-C)U(B-C) be arbitrary

x∈ (A-C) or x ∈ (B-C)

{x ∈ A but x ∉ C} or { x ∈ B but x ∉C}

{x ∈A or x ∈ B} but x ∉ C

x ∈ (AUB) but x ∉ C

x ∈(AUB)-C

x∈(A-C)U(B-C) = x∈(AUB)-C

therefore (A-C)U(B-C)=(AUB)-C

hence proved