1) Prove that angle inscribed in a semicircle is a right angle.
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Prove that the angle in a semicircle is a right angle.
∴∠AOB=2∠APB (∠AOB is the subtended at center which is equal to 180∘ and ∠APB is the angle made at any point on the circle.) Hence, it can be said that the angle in a semicircle is a right angle
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Now POQ is a straight line passing through center O.
∴ Angle subtended by arc PQ at O is
∠POQ=180°
The angle subtended by an arc at the center is double the angle subtended by it any point on the remaining part of the circle.
∴∠POQ= 2∠PAQ
∠POQ/2 =∠PAQ
180 / 2 =∠PAQ
∠PAQ=90
Hence proved.
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