(1-sin²theta)(1-tan²theta)=1
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Step-by-step explanation:
(1-sin²¢)(1-tan²¢) =1
LHS
= (1-sin²¢)(1-tan²¢)
we know that...
(1-sin²¢) = (Cos²¢) and , (1-tan²¢)= (Sec²¢)
= (Cos²¢)(Sec²¢)
=1
= RHS ( proved)
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