(1-sin²theta)sec²theta sec²theta=1 prove
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{1-sin^2theta}=cos^2theta sec^theta=1=÷cos^2theta cos^2theta÷cos^2theta=1
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(1-sin²θ)sec²θsec²θ = 1
⇒ cos²θ sec²θsec²θ = 1 (∵ sin²θ + cos²θ = 1)
⇒ sec²θ = 1 (∵cos²θ = 1/sec²θ)
or If you wrote the question wrong (which I presume you have)
cos²∅sec²∅ = 1
cos²∅ × (1/cos²∅) = 1
1=1
⇒ cos²θ sec²θsec²θ = 1 (∵ sin²θ + cos²θ = 1)
⇒ sec²θ = 1 (∵cos²θ = 1/sec²θ)
or If you wrote the question wrong (which I presume you have)
cos²∅sec²∅ = 1
cos²∅ × (1/cos²∅) = 1
1=1
Annabeth:
please mark as brainliest!
why? what you say i didn't understand
As if yours is understandable.
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