Question

1+sina/1-sina=coseca+1/coseca-1

Answer 1

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Answer 2

$LHS = \frac{1 + sinA}{ 1 - sinA }$

/* Dividing numerator and denominator by sinA , we get */

$= \frac{\frac{1 + sinA}{sinA}}{ \frac{1 - sinA}{sinA} }$

$= \frac{\frac{1}{sinA} + \frac{sinA}{sinA}}{\frac{1}{sinA} - \frac{sinA}{sinA}}$

$= \frac{cosec A + 1}{ Cosec A - 1 }$

$\boxed {\pink { Since, \frac{1}{sin A } = Cosec A }}$

$= RHS$

Therefore.,

$\red{ \frac{1 + sinA}{ 1 - sinA }}\green {= \frac{cosec A + 1}{ Cosec A - 1 } }$

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