1 Solve the following quadratic equations by completing the square .
Attachments:
Answers
Answered by
0
GIVEN
x^2 + 3x + 1 = 0
2ab = 3
Where a = 1
2 x 1 x b = 3
b = 3 / 2
(x + 3/2)^2 - (3/2)^2 + 1 = 0
(x + 3/2)^2 - (9/4) + 1 = 0
(x + 3/2)^2 - (5/4) = 0
(x + 3/2)^2 = 5/4
x + 3/2 = + - root 5 / 2
x = + - (root 5 / 2) - 3/2
x = (root 5 - 3) / 2 & - (root 5 + 3) / 2
x^2 + 3x + 1 = 0
2ab = 3
Where a = 1
2 x 1 x b = 3
b = 3 / 2
(x + 3/2)^2 - (3/2)^2 + 1 = 0
(x + 3/2)^2 - (9/4) + 1 = 0
(x + 3/2)^2 - (5/4) = 0
(x + 3/2)^2 = 5/4
x + 3/2 = + - root 5 / 2
x = + - (root 5 / 2) - 3/2
x = (root 5 - 3) / 2 & - (root 5 + 3) / 2
Similar questions