Math, asked by fazalshaik812, 8 months ago

(1 + tan 0 + sec 0) (1 + coto - cosec 0)

Answers

Answered by rishabhdasxe265
45

Answer:

2

Step-by-step explanation:

(1+tanA+secA) (1+cotA-cosecA)

=(1+\frac{sin a}{cos a}+\frac{1}{cos a})(1+\frac{cos a}{sin a}-\frac{1}{sin a})

=(\frac{cosa+sina+1}{cos a})(\frac{sina+cosa-1}{sina})

=\frac{(cosa+sina)^{2}-1^{2}  }{sina cosa}

=\frac{sin^{2}a+cos^{2}a+2sinacosa -1 }{sina cosa}

=\frac{1+2sina cosa -1}{sina cosa}

=\frac{2sina cosa}{sina cosa}

= 2

pls mark as brainliest!!!!!

p.s. instead of 0 i have written a

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