Question

(1 + tan 0 + sec 0) (1 + coto - cosec 0)
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Answer 1

Answer:

2

Step-by-step explanation:

(1+tanA+secA) (1+cotA-cosecA)

=(1+$\frac{sin a}{cos a}$+$\frac{1}{cos a}$)(1+$\frac{cos a}{sin a}$-$\frac{1}{sin a}$)

=($\frac{cosa+sina+1}{cos a}$)($\frac{sina+cosa-1}{sina}$)

=$\frac{(cosa+sina)^{2}-1^{2} }{sina cosa}$

=$\frac{sin^{2}a+cos^{2}a+2sinacosa -1 }{sina cosa}$

=$\frac{1+2sina cosa -1}{sina cosa}$

=$\frac{2sina cosa}{sina cosa}$

= 2

pls mark as brainliest!!!!!

p.s. instead of 0 i have written a