Math, asked by arnavgawde2810, 6 months ago

(1+tan^2 θ) (1+sinθ) (1-sinθ)​

Answers

Answered by nanimanas1
1

Answer:

1

Step-by-step explanation:

(1+tan²θ)(1+sinθ)(1-sinθ)

then it is

(1+tan²θ)(1-sin²θ)

(1+tan²θ)(cos²θ)

since

sin²x+cos²x=1

and then

now

(1+sin²θ/cos²θ)(cos² θ)

(cos²θ+sin²θ)(cos² θ)/(cos² θ)

then

(1)(1)

is 1

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