(1+tan^2 θ) (1+sinθ) (1-sinθ)
Answers
Answered by
1
Answer:
1
Step-by-step explanation:
(1+tan²θ)(1+sinθ)(1-sinθ)
then it is
(1+tan²θ)(1-sin²θ)
(1+tan²θ)(cos²θ)
since
sin²x+cos²x=1
and then
now
(1+sin²θ/cos²θ)(cos² θ)
(cos²θ+sin²θ)(cos² θ)/(cos² θ)
then
(1)(1)
is 1
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