Question

(1+tanA÷1-cotA)^2 = tan^2A

Answer 1

Answer:

(1+tanA/1-cotA)^2=tan^2A

{1+tanA×1-(1/cotA)}^2=tan^2A

(1-1/cotA+tanA-tanA/cotA)^2=tan^2A

(1+tanA-1-tanA/cotA)^2=tan^2A {take LCM of 1/cotA & tanA/cotA}

(1+tanA-1-tanA+tanA)^2=tan^2A { cotA=1/tanA}

(tanA)^2=tan^2A

tan^2=tan^2A

hence proved