1. the ball is thrown vertically upward with an initial distance of 20 m / s. if g = 10 m / s, the maximum height of the ball is....
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Is known: v0= 20 m/s
g = 10 m/s
v = 0
Asked: h.........?
Answer:
0²= (20 m/s)² - 2 x 10² x h
0= 400 m²/s² - 20 m/s² x h
20 m/s² x h= 400 m²/s²
so its result:
h= 400 / 20= 20 m
I hope this helps
-GoodLuck-
g = 10 m/s
v = 0
Asked: h.........?
Answer:
0²= (20 m/s)² - 2 x 10² x h
0= 400 m²/s² - 20 m/s² x h
20 m/s² x h= 400 m²/s²
so its result:
h= 400 / 20= 20 m
I hope this helps
-GoodLuck-
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