Question

1.
The gaseous system has a volume of 580 cm at a certain pressure. If its pressure is increased by 0.96
atm, its volume becomes 100 cm. Determine the intial pressure of the system
Hint: (P x 580 = (P + 0.96) 100]
a) 0.4 atm
b) 0.2 atm
c) 0.6 atm
d) 0.1 atm​

Answer 1

Answer:

0.2 atm

Solution :

P1=P atm , P2=(P+0.96) atm

V1=580cm3 , V2=100cm3

Since temperature is constant, Boyles' Law is applicable.

P1V1=P2V2 or (Patm)×(580cm3)=(P+0.96)atm×(100cm3)

(P+0.96)atm=P×(580cm3)(100cm3)=5.8P,4.8P=0096atm or P=(0.96atm)4.8=0.2 atm

Answer 2

Answer:

Explanation:

Applying Boyle's law

P ×580 = (P + 0.96)100

⟹ P=0.2 atm