Question

1. The sum of numerator and denominator of a fraction is 3 less than twice
the denominator. If each of the numerator and denominator is
decreased by 1, the fraction becomes 1/2. Find the fraction. ​

Answer 1

Answer:

Let the numerator be x and denominator be y.

Let the fraction be  

y

x

​  

 

x+y+3=2y

(or) x−y=−3

(or) x=y−3 _____ (1)

Also ,  

y−1

x−1

​  

=  

2

1

​  

 

x−1=  

2

y−1

​  

 

x=  

2

y−1

​  

+1⇒2x=y−1+2=y+1

(or) 2x−y=1 _____ (2)

substituting (1) in (2),  

2(y−3)−y=1

⇒2y−6−y=1⇒y=7

put y=7 in (1) we get x=7−3=4

∴x=4,y=7

∴ the fraction is  

y

x

​  

=  

7

4

​

Step-by-step explanation: