Question

1) The total number of lions and peacocks in a certain zoo is 50. The total number of their legs
is 140. Then find the number of lions and peacocks.​

Answer 1

Answer:

number of lions = 20

number of peacocks =30

Step-by-step explanation:

let number of lions be = x

let number of peacocks be = y

eq (1)

x + y = 50

eq (2)

total number of legs is given by -

number of lions × 4 + number of peacocks ×2

i.e

4x + 2y = 140

on solving both equations we get x = 20 and y = 30

Thank you

Answer 2

Given :

• The total number of lions and peacocks in a certain zoo is 50

•And the total number of their legs =140

To Find :

• The number of lions and peacocks in a zoo=?

Solution :

Let us assume that the number of lions be "x"

And the number of peacocks be "y"

According to given conditions :

$\implies \bf \: x + y = 50$

$\implies \bf \: x = 50 - y \: \: \: ....(1)$

Therefore, the total number of legs =140

So, the lion having 4 legs

And the peacock having 2 legs

According to the question equation will be :

$\implies \bf \: 4x + 2y = 140$

(Solve this equation)(And put the value of "x" in this equation)

Substituting the equation (1) in given equation :

$\implies \sf \: 4(50 - y) + 2y = 140$

$\implies \sf \: 200 - 4y + 2y = 140$

$\implies \sf \: 2y = 60$

$\implies \boxed{ \sf{y = 30}}$

Therefore, the value of y is 30

Now, from equation (1)

$\implies \sf \: x = 50 - y$

$\implies \sf \: x = 50 - 30$

$\implies \boxed{ \sf{x = 20}}$

Therefore, the value of x is 20

⇒ The total number of lions (x) =20

⇒The total number of peacocks (y) =30