Question

(1) Two pendulums have length 81 cm and 1.44cm . Find the ratio of their
1) Time periods
2) Frequency

(2) draw a graph of l , the lenght of simple pendulum against t2 , the square of its time period

Answer 1

the formula of time period of a pendulum is T=√l/g...............where l is the length of the pendulum

therefore , the time period is directly propotional to the under root of length

T1/T2= √L1/L2

           √81/1.44

            9/1.2= 90/12

            15/2

frequency is inversly propotional to the time period

n1/n2= 2/15

Answer 2

1)

1)7.45sec

2)0.1329 Hz