Question

1 ] what is pythagoras theorem?
2]In a triangle ABC right angled at A,find the length of side BC, where AB=8 cm , AC=15 cm.
3]In a triangle PQR right angled at Q,find the length of side PQ, where QR=8 cm , PR=10 cm.

plz answer all the questions.

Answer 1

Pythagoras theorem was stated by a scinsist pytha Pythagoras theorem states that
in a right angled triangle the square of its hypot= the square outs base+the square of its perpendicular

i)
C
| \
| \
| \
|____\
A B
BC2= AB2 + AC2

BC2=8×8+15×15
BC2= 64+225
BC2=289
BC×BC=289
__
BC= /289
BC = 17cm

ii) P
| \
| \
| \
| \
|____\
Q R
PR2= PQ2+QR2
10×10=PQ2+8×8
100=PQ2+64
PQ2=100-64
PQ2=36
___
PQ=/ 36
PQ=6

Answer 2

1. Pythagoras theorem =
Hypo square = side square+ side square

2. BC square = AC square + AB square
15 square + 8 square
289 = BC square
BC = 17 cm

3.PR square = PQ square + QR square
10 square = 8 square + OR square
100 - 64
QR square = 36
QR = 6 cm