Question

1) Write down the first four terms of the sequences whose general terms are Tn = 3n+1​

Answer 1

Step-by-step explanation:

Tn = 3n + 1

first term T1

= 3(1) + 1

= 3 + 1

= 4

second term T2

= 3(2) + 1

= 6 + 1

= 7

third term T3

= 3(3) + 1

= 9 + 1

= 10

Fourth term T4

= 3(4) + 1

= 12 + 1

= 13

the AP is 4, 7, 10, 13..........

Answer 2

The first four terms of the sequence are 4, 7, 10, and 13.

Given:

• General terms are $T_n = 3n+1$

To find:

• Write down the first four terms of the sequences whose general term is given.

Solution:

Concept to be used:

• Put the value of n as 1,2,3, and 4.

Step 1:

Put n=1.

$T_n = 3n + 1$

or

$T_1 = 3(1) + 1$

or

$\bf T_1 = 4$

Step 2:

Put n=2.

$T_2 = 3(2) + 1$

or

$\bf T_2 =7$

Step 3:

Put n= 3

$T_3 = 3(3) + 1$

or

$\bf T_3 = 10$

Step 4:

Put n= 4

$T_4 = 3(4) + 1$

or

$\bf T_4 = 13$

Thus,

The first four terms of the sequence are 4, 7, 10, and 13.

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