Question

1. Write the opposite of the following statement: (1) 7 de gree celsius above
freezing point () 10 minutes after the blast of missile (ii) walking 12m
forward. (iv) I hour before the arrival time of train
2. Find the product of the following: (1) (-1) (-3)× 6 (II) (-5) ×(-5) × (-5)
(iii) (-10) x 0x (-18) (iv)0 x (-9) (-9)
3. Find the quotient : (0) 120-3 (i) 343 +7 (ii) 108 + (-12) (iv) - 128 + 8
4. Convert the following improper fractions into mixed fraction :
5. help me fast plz plz
6. Determine the integer whose product with (-1) is - 105.
7. Find the quotient of(-95) ÷ 5​

Answer 1

7 degree celsius below
10 minutes before the blast of missile
Walking 12m backward
1 hour before the arrival of train
Question 2answers
18
-75
0
0
Question 7answer
-19

Sorry in rest answers i am not sure

Answer 2

Opposite Of The Statements Are:-

1) 7 degrees celsius above freezing point.

• 7 degrees celsius below freezing point.

2) 10 minutes after the blast of missile.

• 10 minutes before the blast of missile.

3) Walking 12m forward.

• Walking 12m backwards.

4) 1 hour before the arrival time of the train.

• 1 hour after the arrival time of the train.

The Product Of The Following Are :-

1) $(- 1)( - 6) \times 3 = 6 \times 3 = 18$

= 18

2) $- 5 \times - 5 \times - 5 = 25 \times - 5 = - 125$

= -125

3) $(-10) \times 0 \times (-18) = 0 \times ( - 18) = 0$

= 0

4) $0 \times (-9) (-9) = 0 \times ( - 9) = 0$

= 0

Value of the following are:-

• $120-3 = 117$
• $343 +7 = 350$
• $108 + (-12) = 108 - 12 = 96$
• $- 128 + 8 = - 120$

The integer whose product with (-1) is - 105

• = 105

By working

• $( - 1) \times 105 = - 105$

The quotient of (-95) ÷ 5

• $\frac{ - 95}{5} = - 19$
• = 19

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