Question

1/x+1 + 1/x-2 = 1/x-3 by qudratic equation​

Answer 1

Answer:

5 or 1

Step-by-step explanation:

=> 1/(x + 1) + 1/(x - 2) = 1/(x - 3)

=> 1/(x + 1) = 1/(x - 3) - 1/(x - 2)

=> 1/(x + 1) = (x-2 - (x-3))/(x-3)(x-2)

=> 1/(x + 1) = (x-2-x+3)/(x-3)(x-2)

=> 1/(x+1) = 1/(x-3)(x-2)

=> (x - 3)(x - 2) = x + 1

=> x² -5x + 6 = x + 1

=> x² - 6x + 5 = 0

Using quadratic equation,

=> x = [-(-6) ±√{6² - 4(1)(5)}]/2(1)

= [6 ± √(36 - 20)] /2

= (6 ± 4)/2

= 10/2 or 2/2

= 5 or 1