Question

1/x^2= 4/(3a-x)^2 solve​

Answer 1

Answer:

$\huge\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Answer}}}}}}}} \\ \large\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Your~answer↓}}}}}}}} \\ \\ \frac{1}{ {x}^{2} } = \frac{4}{ {(3a - x)}^{2} } \\ = > \frac{1}{x} = \frac{2}{3a - x} \: or \: \frac{1}{x} = - \frac{2}{3a - x} \\ 3a - x = 2x \: or \: 3a - x = - 2x \\ 3x \: = 3a \: or \: x = - 3a \\ x = a \: or \: x \: = - 3a$

Answer 2

this

is

correct

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