Math, asked by asirsolomen, 11 months ago

1/x-2/y+4=0; 1/y-1/z+1=0; 2/z+3/x=14 solve this linear equation in three variables​

Answers

Answered by Amala13
7

Step-by-step explanation:

Linear equations answer

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asirsolomen: x+20=3y/2+10=2z+5=110-(y+z) solve linear equations in three variables​
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Answered by nikhilasri0485
0

Step-by-step explanation:

1/x-2/y+4=0. 1/y-1/z+1=0. 2/z+3/x=14

a-2b=-4____1. b-c=-1_____2. 2c+3a=14_____3

sub eq 2*2 from

eq 1,

a-2b=-4

(-)2c+2b=-2

__________

a-2c=-6___4

__________

add eq 3 and eq 4,

2c+3a=14

-2c+ a=-16

__________

4a=8

____________

a=8/4

a=2

put a =2 in eq 1,

a-2b=-4

2-2b=-4

2b=6

b=6/2

b=3

put b=3 in eq 2,

3-c=-1

-c=-4

c=4

a=1/x

x=1/a

x=1/2

b=1/y

y=1/b

y=1/3

c=1/z

z=1/c

z=1/4

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