Question

when a two digit number is divided by the sum of its digits the quotient is 8. If the ten's digit is diminished by three times the unit's digit, the remainder is 1. What is the number?

Answer 1

Let x be the ones and y be the tens digit of a number. Acordingly:-

10y+x=8(x+y). or. 2y -7x =0………….(1)

y-3x=1…………………..(2)

Solving the two equations x=2. , y =7.

The number= 10y+x=10×7+2 =72. Answer

Answer 2

This is my answer hope this helpfull for everyone.