Question

1. (x+4)³ . 2. (y-2)³.​

Answer 1

Step-by-step explanation:

1.(x+y)^3 = x^3 + 3x^2y +3xy^2 + y^3

X=x ,y=4

=x^3 + 3x^2×4+3x × 4^2 + 4^3

=x^3 + 3x^2×4+3x × 16 +64

=x^3 + 3x^2×4+3x × 80

= x^3 + 3x^2× 3x ×4+80

= x^3 + 3x^2× 3x × 84

2.(x-y)^3=x^3 - 3x^2y +3xy^2 - y^3

x=y ,y=2

=y^3 - 3y^2×2 +3y ×2^2 - 2^3

=y^3 - 3y^2×2 +3y ×4 - 8

=y^3 - 3y^2×2 +3y × -4

=y^3 - 3y^2 + 3y × 2 - 4

=y^3 - 3y^2 + 3y × -2

Answer 2

Answer:

by using formula

(a+b)^3. and by (a-b)^3

very simple to solve this ques.