Question

10^2017-2017 is expressed as integer,what is the sum of it's digits

Answer 1

Answer:

Given: $10^{2017}-2017$  

if $10^x$ -2017 = last 4 digits are always 7, 9, 8 and 3

$10^4$ -2017 = 7983

$10^5$ -2017 = 97983

$10^6$ -2017 = 997983

$10^7$ -2017= 9997983 and so on...

If x>1, then

The sum of the digits $= (x-4) \cdot 9 +7+9+8+3$

hence, $(2017-4) \cdot 9 +7+9+8+3$ = $2013 \cdot 9 +7+9+8+3$

= 18117+7+9++8+3 = 18,144

Therefore, the sum of it's digit is, 18,144

 

 

Answer 2

Answer:

-2017 = last 4 digits are always 7, 9, 8 and 3

-2017 = 7983

-2017 = 97983

-2017 = 997983

-2017= 9997983........

If x>1, then

The sum of the digits

hence,  =  18117+7+9++8+3 = 18,144

Therefore, the sum of it's digit is, 18,144