Math, asked by vaiinepali674, 3 months ago


10 – [41 – {28 + (12 – 2)}] – 28 ÷ 4​

Answers

Answered by sumathimohan485
2

Answer:

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Answered by priyasamanta501
2

Solution:-

10-[41-{28+(12-2)}]-28÷4

=10-[41-{28+10}]-7

=10-[41-38]-7

=10-3-7

=10-10

=0

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