Question

10) A 15 m long ladder reached a window 12 m high from the ground on placing it against a
wall at a distance a. Find the distance of the foot of the ladder from the wall.
11) A tree is broken at a height of 5 m from the ground and its top touches the ground at a
distance of 12 m from the base of the tree. Find the original height of the tree.
12)The side of the triangle are of length 7.5 m, 4 m, 8.5 m. Is this triangle a right triangle?
so, which side is the hypotenuse?
13) A park is 90 m x 90 m square. How long is a diagonal across the park?
Find the value of the unknown exterior angle in the below figures​

Answer 1

Answer:

11 ka bata raha hun

Ismein Pythagoras theorm lagega

Ab square =bc square+ac square

Ab square =12 square+5 square

Ab square=144+25

Ab square=169

√169=13

After it has broken 5m

So original height=13+5=18m ans

Agar sahi to plzzz mark it the BRAINIEST answer

Answer 2

Hello, So these may help you to some extent..

Answer:

1) Here 12m is the perpendicular and 15m is the Hypotenuse

Therefore, by using Pythagoras theorum:-

H^2= p^2+b^2

b^2=h^2-p^2

b^2=15^2 - 12^2

b^2=225-144

b^2=81

b=9

2)

5m=p

12m=b

therefore to find Hypotenuse:-

H^2=P^2+b^2

h^2= 5^2+12^2

h^2= 25+144

h^2= 169

h= 13

therefore, original height of the tree is:- 13+5=18m

sorry I cannot solve the rest two, but hope this helps you^-^