10. a) A field is in the shape of a trapezium whose parallel sides are 25m and 10m. the non-parallel sides
Are 14m and 13m. Find the area of the field.
b) Show that in a right- angled triangle, the hypotenuse is the longest side
plz give the right answer
Answers
Answer:
Go to the book and check your questions
Answer:
196m^2
Step-by-step explanation:
let the given field be the shape of a trapezium ABCD in which AB=25m,CD=10m,BC=13m and AD=14m.
From D,draw De//BC meeting AB at E
Now draw DFperpendicular to AD
DE=BC=13m
AE=AB-EB
=25-10=15m
For triangle AED
a=14m,b=15m,c=13m
S=a+b+c/2
=14+13+15/2
=42/2
=21m
area of triangle AED=√s(s-a)(s-b)(s-c)
=√21(21-14)(21-15)(21-13)
=√21*7*6*8
=√7*3*7*2*3*4*2
=7*3*2*2
=84m^2
DF perpendicular to AE
For triangle ADE
Area of triangle ADE=1/2bh
=1/2*15*h
IE, 1/2*15*h=84
h=84*2/5
=56/5m
Height of the parallelogram EBCD=56/5m
Area of the parallelogram ABCD=b*h
=10*56/5
=112m^2
Area of the field = 84m^2+112m^2
=196m^2
