Question

10. A car accelerates from rest at a constant rate a for
some time, after which it decelerates at a constant
rate B and comes to rest. If the total time elapsed is t,
then the maximum velocity acquired by the car is :
a² – B²)
aßt
(3)
(a + B)t
aß
a+ß​

Answer 1

Explanation:

Maximum velocity will be aBt/(a+B)