Question

the velosity of a particle moving along the x axis varies according to the expression Vx=40-5t2 whereVx is metre per second and t is in seconds the average accelaration in the time interval t=0 to t=2s is​

Answer 1

Answer:Explain the contribution of agriculture to the national economy employment and output?​

Explanation:

Answer 2

answer : -10m/s²

The velocity of a particle moving along the x-axis varies according to the expression, Vx = 40 - 5t²

we have to find average acceleration in the time interval t = 0 to t = 2s.

we know, rate of change of velocity with respect to time is known as acceleration.

so, a = dVx/dt = d(40 - 5t²)/dt = -10t

now, average acceleration in time interval (t = 0 to t = 2s ) ;

= {acceleration at( t = 0) + acceleration at (t = 2s)}/2

= {-10(0) + (-10)(2)}/2

= -10 m/s² [here negative sign indicates that acceleration is just opposite direction of its motion. ]