Question

10. A farmer had fodder for 40 animals for 60 days. He
bought some more animals and the fodder lasted for
50 days. How many animals did he buy?

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Answer 1

Answer:

48 animals

Step-by-step explanation:

Given:

• farmer had fodder for 40 animals for 60 days.
• He bought some more animals and the fodder lasted for 50 days.

To find:

• How many animals did he buy?

Solution:

Let the farmer bought x number of animals.

Number of animals = 40 | x

Number of days = 60 | 50

So, here when the number of days decrease the number of animals increase.

∴ It is a case of inverse variation.

In inverse variation, x₁y₁ = x₂y₂

Here,

x₁ = 40

y₁ = 60

x₂ = x

y₂ = 50

• 40 × 60 = x × 50
• x = (40 × 60)/50
• x = ( 4 × 60)/5
• x = 4 × 12
• x = 48

∴ Farmer bought 48 animals.

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Answer 2

Step-by-step explanation:

U didn't take a picture of me when we were in the meeting right?...like u didn't record anything?