Question

10) A right-angled triangle has a base of 40 cm, height
of 30 cm and hypotenuse of 50 cm. The triangle is
rotated so that the hypotenuse forms the base.
Find the altitude now.​

Answer 1

Answer:

a=

9−l

2

b=

16−l

2

⇒a+b=5

a=5−b

a

2

=25+b

2

−l

2

−10b

9−l

2

=25+16−l

2

−10

16−l

2

10

16−l

2

=32

16−l

2

=3.2

16−l

2

=10.24

l

2

=5.76

⇒l=2.4cm

Hence, the answer is 2.4cm.

Step-by-step explanation:

hope this helps.....

Answer 2

Answer:

$area \: of \: the \: given \: triangle \\ = \frac{1}{2} \times 40 \times 30 {cm}^{2} \\ = 600 {cm}^{2} \\ \: after \: rotating \\ base = 50cm \: and \: area = 600 {cm}^{2} \\ \frac{1}{2} \times base \times 50 = 600 \\ base = 24cm \\ hence \: the \: \: altitude \: after \: rotation \\ is \: 24cm$