Question

10 cubes are placed adjacent to each other in a row.Find the ratio of the T.S.A of the cuboid formed to the sum of the TSA of the 10 cubes.

Please help me with this.

Answer 1

Hey buddy!!!


Let the side of the cube be x cm
Then, the length of the cuboid formed after joining 10 cubes of side x cm = 10x cm

TSA of 1 cube = 6a^2
= 6x^2
TSA of 10 cubes = 10× 6x^2
= 60x^2

Length of the cuboid = 10x cm
Breadth of the cuboid = x cm
Height of the cuboid = x cm
Then,
TSA of cuboid = 2(lb + bh + hl)
= 2[(10x × x) + (x × x) + (x × 10x)]
= 2(10x^2 + x^2 + 10x^2)
= 2 × 21x^2
= 41x^2

Now,
Ratio of TSA of the new cuboid to the sum of TSA of the 10 cubes = 41x^2/60x^2
= 41:60

Hope it is correct...
If so, please mark it as brainliest!!!

Regards...