Question

10. Find the value of k for which the roots are real and equal , 3x2-5x + 2k=0​

Answer 1

Step-by-step explanation:

compare the equation with ax^2 + bx + c

Here a = 3 , b= -5 and c = 2k

D= b^2 - 4ac

For real and equal roots D=0

so,( -5)^2 - 4×3×2k=0

25-24k=0

-24k=-25

k= 25/24