10 g of ethanol is dissolved in 50g of water calculate the mole fraction of each components
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mass of ethanol =10 g
mass of ethanol =10 g molar mass [C2H5OH]=46
mass of ethanol =10 g molar mass [C2H5OH]=46mass of water = 50 g
mass of ethanol =10 g molar mass [C2H5OH]=46mass of water = 50 gmolar mass of H2o = 18
mass of ethanol =10 g molar mass [C2H5OH]=46mass of water = 50 gmolar mass of H2o = 18moles of C2H5OH= 10 ÷46
mass of ethanol =10 g molar mass [C2H5OH]=46mass of water = 50 gmolar mass of H2o = 18moles of C2H5OH= 10 ÷46 =0.22 mol
mass of ethanol =10 g molar mass [C2H5OH]=46mass of water = 50 gmolar mass of H2o = 18moles of C2H5OH= 10 ÷46 =0.22 molmoles of H2O = 50÷ 18
mass of ethanol =10 g molar mass [C2H5OH]=46mass of water = 50 gmolar mass of H2o = 18moles of C2H5OH= 10 ÷46 =0.22 molmoles of H2O = 50÷ 18 = 2.78 mol.
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