Question

10 litres of a mixture of propane (60%) and butane (40%)is burnt calulate the total volume of Co2 formed​

Answer 1

Answer:

From the given data we can deduce that C3H8 + 5O2 -> 3CO2 + 4H2O .

Again, we can say that equation as 2C4H10 + 13O2 -> 8CO2 + 10H2O .

Since the number of moles of propane is 1 and it gives 3 moles CO2.

So, we know that the 60 ml of propane will give 3 X 60 = 180 ml CO2.

While 2 moles of butane gives 8 moles CO2.

Hence, we know that 40 ml of butane will give = 8 X 40/2 = 160 ml of CO2 .

Then accordingly total carbon dioxide formed is 340 mL.

So, according to the question when 10 litres  is burnt then 34mL of COwill formed.

Answer 2

Explanation:

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