Math, asked by Annamr4801, 1 year ago

10 men can complete a project in 12 days 12 children can complete the same project in 16 days and 8 women can complete the same project in 20 days. 5 men and 12 children started working on the project if after 4 days 8 children were replaced by 4 women. in how many days the remaining project was completed?

Answers

Answered by thogilan
1
already the project was completed..
so there is no remaining work in the project.
Answered by rikimunni
2

Answer:

6and2/21days

Step-by-step explanation:

ATQ  

10m×12:12C×16:8W×20  

15M=24C=20W  

M=15  

C=24  

W=20  

LCM of these 120  

Now there efficiencies are  

M=8  

C=6  

W=5  

Total work=10×12×8=960  

ATQ  

4 days work of 5 men and 12 children=(5×8+12×6)×4=448

Now remaining 512 work is done by 5 men 4 children and 4 women  

Then  

It is done in =512/84=6 2/21


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