Chemistry, asked by rajatarora4972, 11 months ago

10 moles SO₂ and 15 moles O₂ were allowed to react over a
suitable catalyst. 8 moles of SO₃ were formed. The remaining
moles of SO₂ and O₂ respectively are -
(a) 2 moles, 11 moles (b) 2 moles, 8 moles
(c) 4 moles, 5 moles (d) 8 moles, 2 moles

Answers

Answered by arindambhatt987641
3

(a) 2 moles, 11 moles

Explanation:

SO₂ + 1/2 O₂ = SO₃

1 mol of SO₂  reacts with  1/2 mol of  O₂ to form  SO₃

now if 8 moles of SO₃  were formed, means 8 moles of SO₂ have reacted .

1 mol of SO₂  reacts with  1/2 mol of  O₂

8  mol of SO₂  reacts with 8*  1/2  = 4 mol of  O₂

moles reacted SO₂ = 8                  left moles SO₂ = 2

moles reacted O₂   = 4                     left moles O₂ = 11

Answered by greathishanth
0

it is your answer hope it is helpful

option (A) is correct

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