10 moles SO₂ and 15 moles O₂ were allowed to react over a
suitable catalyst. 8 moles of SO₃ were formed. The remaining
moles of SO₂ and O₂ respectively are -
(a) 2 moles, 11 moles (b) 2 moles, 8 moles
(c) 4 moles, 5 moles (d) 8 moles, 2 moles
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(a) 2 moles, 11 moles
Explanation:
SO₂ + 1/2 O₂ = SO₃
1 mol of SO₂ reacts with 1/2 mol of O₂ to form SO₃
now if 8 moles of SO₃ were formed, means 8 moles of SO₂ have reacted .
1 mol of SO₂ reacts with 1/2 mol of O₂
8 mol of SO₂ reacts with 8* 1/2 = 4 mol of O₂
moles reacted SO₂ = 8 left moles SO₂ = 2
moles reacted O₂ = 4 left moles O₂ = 11
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it is your answer hope it is helpful
option (A) is correct
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