Question

10 numerical and answer in chapter 8 motion​

Answer 1

Answer:

By which book I am student of class 9 If you are also student of class then please tell and please tell me physics questions whose answer you want

Answer 2

Explanation:

example 8.3

solution :-

Total distance covered by Usha in 1 min is 180 m.

Displacement of Usha in 1 min = 0m.

Average speed = Total distance covered/ Total time taken.

= 180m/1min = 180m 1min

______ × ______

1 min 60s

= 3ms^-1

Average velocity = Displacement / Total time taken.

= 0m/ 60s

= 0ms^-1

The average speed of Usha is 3ms^-1

and her average velocity is 0 ms^-1.

Hope this will help you