Question

10 raised to 23 atoms of carbons mass in gm

Answer 1

Hey there !

Formula used :

Given mass/Molar mass = No. of atoms/ Avogadro’s constant

Let the mass be “x”

=> x/12 = 10²³/6.022*10²³. [ molar mass of C = 12g]

=> x = 12/6.022

=> x = 1.99 = 2 (approx.)

Hence the mass is 2g approximately.

Hope this helps ya