position x=t^2-4t+6. find distance and position in 3 seconds
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Hello! ! !
Hey dear here is your answer_________
given,
x = t^2 - 4t + 6
differentiate X with respect to t we get,
dx/dt = 2t - 4
we have to find distance in 3 seconds
ie. t = 3
[(dx/dt)at t= 3] = 2 × 3 - 4 = 2
the distance is 2 units.
Now position,
x = (3)^2 - 4(3) + 6
x = 9 - 12 + 6
x = 3
the position x = 3 units
________________________
Hope this answer will help u....
-----@Neha...
Hey dear here is your answer_________
given,
x = t^2 - 4t + 6
differentiate X with respect to t we get,
dx/dt = 2t - 4
we have to find distance in 3 seconds
ie. t = 3
[(dx/dt)at t= 3] = 2 × 3 - 4 = 2
the distance is 2 units.
Now position,
x = (3)^2 - 4(3) + 6
x = 9 - 12 + 6
x = 3
the position x = 3 units
________________________
Hope this answer will help u....
-----@Neha...
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