Question

10. Two beakers with 100ml water is taken- A and B. A few crystals of KMnO⁴ are added in a.
Solis changes
and honey is added in B-
a. What changes are observed in the two beakers.
b. In which beaker has the change occurred more quickly?
c. Name the process involved in the observed change.
d. Why is the time taken for the change to occur different in the two beakers?
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Answer 1

Answer:

a) ans: ◾ when we add potassium permanganate crystals into beaker A containing water...it will immediately dissolve in water and change its colour to purple.

◾ when we add honey to beaker B , containing water...it will not dissolve immediately and we wouldn't be able to observe any difference in the colour.

b) ans: It can be observed that the change is occured in Beaker A more quickly.

c) The process involved in the observed change is called diffusion.

d) ans : we can observe that both the mixtures take different amounts of time because the kinetic energy of the particles depends on the density.

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Answer 2

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