Question

10 women can do a piece of work in 20 days. If 2 of the women deny to work, then how many days are required to complete the work?

Answer 1

10 women can do a piece of work in 20 days.
so, 1 woman can do a piece of work in 10 × 20 = 200 days.

A/C to question,
now, 8 woman have to do same work.
so, use formula $M_1D_1=M_2D_2$

10 × 20 = 8 × D

D = 200/8 = 25 days

hence, 25 days are required to complete the work.

Answer 2

Hey there !

10 women  can complete a work in 20 days

In one day , 10 women can complete 1/20 th  part of work

now ,

1 women can complete 1/200 part of work each day

Given in the question ; 2 of the women denied to work .

Remaining women = 10 - 2 =  8

Each day , 8 women can complete 8/200 = 1/25

required part of work to be done = 1

So working for 25 days , They can complete work . ( each day 8 women can complete 1/25 of work)

Therefore , A work which can be completed in 20 days by 10 women can be done in 25 days if 2 women denies to work .