Question

10. Write the smallest number which when divided by 30, 45 and 60 leaves remainder 8 in each case,​

Answer 1

Step-by-step explanation:

first find factor of all numbers by LCM

30=3*2*5

45=3*3*5

60=3*2*2*5

now HCF is 3*5=15

And LCM is 2*3*2*2*15=360

• now 360 is the number when divide by 30,45 and 60 leaves remainder 8.

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