Question

There are n electrons of charge e on a drop of
oil of density p. It is in equilibrium in an electric
field E. Then radius of drop is


plzz explain fast​

Answer 1

Answer:

The drop is in equilibrium due to cancelling out of gravitational force and the electric force acting on it

Electric Force =E×ne

Gravitational Force = 34

πr 3 ρg 34 πr 3 ρg=Ene⇒r= 3

4πρg3Ene

Explanation:

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Answer 2

Explanation:

since in equlibrium electtistatic force = gravitational force and mass = volume × density

here since drop is a sphere v= 4/3 pi r³