Question

10^x=64 then find the value of x

Answer 1

Oh boy...

So given equation

10^x = 64

Take log on both sides

log (10^x) = log 64

If you have studied logarithms, you should know the rules

log (10^x) = log ( 8^2)

x log10 = 2 log8                                      [ ∵ log (a^b)= b loga]

x = 2 log ( 2^3)                                         [ ∵ log 10 = 1]

x = 6 log2

Taking approx value of log 2 ( had to use a  calculator)

i.e. log 2 = 0.301

x = 6 * 0.301

x = 1.806

That's the value of x.

I hope you understand.

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P.S. This question is incomplete , the original one was find the value of 10^x/2   + 1

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