Math, asked by piyushprajapat0635j, 5 months ago

10 years ago Adam was one third of Bob's age. Two years from now Bob will be one more than twice adem's age. How old are Adam and Bob now? ​

Answers

Answered by faiyazahamad1
0
Let Adam and Bob persent age be x and y
Before 10 age,
Adam’s age = x - 10
Bob’ s age = y - 10
X -10 = (y -10) / 3
3x -30 = y - 10
3x - y = 20 Equ (1)
Tow years from now,
Adam’s age = x + 2
Bob’s age = y + 2

Y + 2 = 1 + 2( x +2)
Y+ 2 = 1 + 2x + 4
y + 2 = 2x + 5

2x - y = -3 Equ (2)
Substract equ (2) from equ (1)
(3x -y) - ( 2x - y) = 20 - (-3)
3x -y -2x + y = 20 + 3

X = 23
Put the value of x in equ(2)
2*23 -y = -3
46 - y = -3
- y = -3 -46
-y = -49

y = 49

Adam’s age be 23 and Bob’s age be 49
Answered by pulakmath007
0

Adam and Bob are now 23 years and 49 years old respectively

Given :

  • 10 years ago Adam was one third of Bob's age.

  • Two years from now Bob will be one more than twice adem's age

To find :

Form the equation to find the age of Adam and Bob now

Solution :

Step 1 of 2 :

Form the equation to find the ages

Here it is given that 10 years ago Adam was one third of Bob's age

Let 10 years ago Bob was 3x years old

∴ 10 years ago Adam was x years old

So Adam and Bob are now (x + 10) years and (3x + 10) years old respectively

Again two years from now Adam and Bob will be (x + 12) years and (3x + 12) years old respectively

By the given condition

\displaystyle \sf  (3x + 12) = 2(x + 12) + 1

Step 2 of 2 :

Calculate age of Adam and Bob now

\displaystyle \sf  (3x + 12) = 2(x + 12) + 1

\displaystyle \sf{ \implies }3x + 12 = 2x + 24 + 1

\displaystyle \sf{ \implies }3x + 12 = 2x + 25

\displaystyle \sf{ \implies }3x - 2x = 25 - 12

\displaystyle \sf{ \implies }x = 13

Present age of Adam

= (x + 10) years

= (13 + 10) years

= 23 years

Present age of Bob

= (3x + 10) years

= (39 + 10) years

= 49 years

Hence Adam and Bob are now 23 years and 49 years old respectively

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