10 years ago Adam was one third of Bob's age. Two years from now Bob will be one more than twice adem's age. How old are Adam and Bob now?
Answers
Before 10 age,
Adam’s age = x - 10
Bob’ s age = y - 10
X -10 = (y -10) / 3
3x -30 = y - 10
3x - y = 20 Equ (1)
Tow years from now,
Adam’s age = x + 2
Bob’s age = y + 2
Y + 2 = 1 + 2( x +2)
Y+ 2 = 1 + 2x + 4
y + 2 = 2x + 5
2x - y = -3 Equ (2)
Substract equ (2) from equ (1)
(3x -y) - ( 2x - y) = 20 - (-3)
3x -y -2x + y = 20 + 3
X = 23
Put the value of x in equ(2)
2*23 -y = -3
46 - y = -3
- y = -3 -46
-y = -49
y = 49
Adam’s age be 23 and Bob’s age be 49
Adam and Bob are now 23 years and 49 years old respectively
Given :
- 10 years ago Adam was one third of Bob's age.
- Two years from now Bob will be one more than twice adem's age
To find :
Form the equation to find the age of Adam and Bob now
Solution :
Step 1 of 2 :
Form the equation to find the ages
Here it is given that 10 years ago Adam was one third of Bob's age
Let 10 years ago Bob was 3x years old
∴ 10 years ago Adam was x years old
So Adam and Bob are now (x + 10) years and (3x + 10) years old respectively
Again two years from now Adam and Bob will be (x + 12) years and (3x + 12) years old respectively
By the given condition
Step 2 of 2 :
Calculate age of Adam and Bob now
Present age of Adam
= (x + 10) years
= (13 + 10) years
= 23 years
Present age of Bob
= (3x + 10) years
= (39 + 10) years
= 49 years
Hence Adam and Bob are now 23 years and 49 years old respectively
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