100.0 grams of water at 4.0°C is heated until its temperature is 37°C. If the specific heat of water is 4.18 J/g°C, calculate the amount of heat energy needed to cause this rise in temperature.
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Answer:
m = 100g
c = 4.18
∆T = 33°C
Q = mc∆T
Q = 100g * 4.18 * 33°C
= 13794J
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