100. In three coloured boxes-Red, Green and
Blue, 108 balls are placed. There are
twice as many balls in the green and red
boxes combined as there are in the blue
box and twice as many in the blue box as
there are in the red box. How many balls
are there in the green box?
(a) 18
(b) 36
(c) 45
(d) 8
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Answer:
Let R, G and B represent the number of balls in red, green and blue boxes respectively.
Then,
R + G + B = 108 ...(i),
G + R = 2B ...(ii)
B = 2R ...(iii)
From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.
Putting G = 3R and B = 2R in (i), we get:
R + 3R + 2R = 108 => 6R = 108 => R = 18.
Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.
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